Given n=$\frac{n}{n+2}$
t3*t4*t5.............*t53=$\frac{3}{5}$ * $\frac{4}{6}$ * $\frac{5}{7}$ .............$\frac{51}{53}$ *$\frac{52}{54}$ *$\frac{53}{55}$
= $\frac{3*4}{54*55} = \frac{12}{2970}$
=$\frac{2}{495}$
Hence,Option(1)$\frac{2}{495}$ is the Answer.