Given : Perimeter of parallelogram=$50$ cm
$\Rightarrow$ $\textrm{50 = 2(L+B)}$ $\left \{ \textbf{Perimeter of Parallelogram = 2(L+B))} \right \}$
$\Rightarrow$ $\textrm{L+B} = \textrm{25}$
Since the length of the parallelogram is $5$ cm more than the width.
$\Rightarrow$ $\textrm{L = B+5}$
Solving this 2 equation we get $\textbf{B =10CM, L=15CM}$
Option $A$ is correct here.