0 votes

The perimeter of a parallelogram is $50$ cm. The length of the parallelogram is $5$ cm more than the width. Find the length of the parallelogram.

- $15$ cm
- $11$ cm
- $5$ cm
- $10$ cm

0 votes

Given : Perimeter of parallelogram=$50$ cm

$\Rightarrow$ $\textrm{50 = 2(L+B)}$ $\left \{ \textbf{Perimeter of Parallelogram = 2(L+B))} \right \}$

$\Rightarrow$ $\textrm{L+B} = \textrm{25}$

Since the length of the parallelogram is $5$ cm more than the width.

$\Rightarrow$ $\textrm{L = B+5}$

Solving this 2 equation we get $\textbf{B =10CM, L=15CM}$

Option $A$ is correct here.

$\Rightarrow$ $\textrm{50 = 2(L+B)}$ $\left \{ \textbf{Perimeter of Parallelogram = 2(L+B))} \right \}$

$\Rightarrow$ $\textrm{L+B} = \textrm{25}$

Since the length of the parallelogram is $5$ cm more than the width.

$\Rightarrow$ $\textrm{L = B+5}$

Solving this 2 equation we get $\textbf{B =10CM, L=15CM}$

Option $A$ is correct here.