Lakshman Patel RJIT
asked
in Quantitative Aptitude
Apr 3, 2020
recategorized
Nov 4, 2020
by Krithiga2101

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Given : Perimeter of parallelogram=$50$ cm

$\Rightarrow$ $\textrm{50 = 2(L+B)}$ $\left \{ \textbf{Perimeter of Parallelogram = 2(L+B))} \right \}$

$\Rightarrow$ $\textrm{L+B} = \textrm{25}$

Since the length of the parallelogram is $5$ cm more than the width.

$\Rightarrow$ $\textrm{L = B+5}$

Solving this 2 equation we get $\textbf{B =10CM, L=15CM}$

Option $A$ is correct here.

$\Rightarrow$ $\textrm{50 = 2(L+B)}$ $\left \{ \textbf{Perimeter of Parallelogram = 2(L+B))} \right \}$

$\Rightarrow$ $\textrm{L+B} = \textrm{25}$

Since the length of the parallelogram is $5$ cm more than the width.

$\Rightarrow$ $\textrm{L = B+5}$

Solving this 2 equation we get $\textbf{B =10CM, L=15CM}$

Option $A$ is correct here.