Lakshman Patel RJIT
asked
in Quantitative Aptitude
Apr 3, 2020
recategorized
Nov 8, 2020
by Krithiga2101

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Best answer

Let first number be $x$, and the second number be $y.$

$(x^{2} - y^{2}) = 45$

$\implies (x - y)(x + y) = 45$

The factors of $45$ are $15, 3, 9, 5, 1$ and $45$

Hence, the possible pairs of numbers are $(9,6), (7,2)$ and $(23,22).$

$\therefore$ The number of such pairs $= 3.$

The correct answer is $(C).$

$(x^{2} - y^{2}) = 45$

$\implies (x - y)(x + y) = 45$

The factors of $45$ are $15, 3, 9, 5, 1$ and $45$

Hence, the possible pairs of numbers are $(9,6), (7,2)$ and $(23,22).$

$\therefore$ The number of such pairs $= 3.$

The correct answer is $(C).$