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What will be area of the rhombus with equations of sides $ax \pm$ $by \pm c$ = $1$ ?

  1. $\frac{3c^{2}}{ab}$sq. units
  2. $\frac{4c^{2}}{ab}$sq. units
  3. $\frac{2c^{2}}{ab}$sq. units
  4. $\frac{c^{2}}{ab}$sq. units
in Quantitative Aptitude 9.3k points 31 523 813
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Option (C)

Consider the given equation as $ax\pm by\pm c = 0$ then, 

The coordinates of the vertices are  (−a/c​,0),(a/c​,0),(0,b/c​),(0,−b/c​)


Let d1​,d2​ be the diagonals of the rhombus. 


d1​ = 2c/a


d2​ = 2c/b


Area = ​1/2(d1​.d2)​ 

= 2*c^2/ab​

ago 76 points 1 2
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