0 votes 0 votes What will be area of the rhombus with equations of sides $ax \pm$ $by \pm c$ = $1$ ? $\frac{3c^{2}}{ab}$sq. units $\frac{4c^{2}}{ab}$sq. units $\frac{2c^{2}}{ab}$sq. units $\frac{c^{2}}{ab}$sq. units Quantitative Aptitude nielit2019feb-scientistd quantitative-aptitude geometry + – Lakshman Bhaiya asked Apr 3, 2020 recategorized Nov 8, 2020 by Krithiga2101 Lakshman Bhaiya 13.7k points 672 views answer comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Option (C) Consider the given equation as $ax\pm by\pm c = 0$ then, The coordinates of the vertices are (−a/c,0),(a/c,0),(0,b/c),(0,−b/c) Let d1,d2 be the diagonals of the rhombus. d1 = 2c/a d2 = 2c/b Area = 1/2(d1.d2) = 2*c^2/ab Aashay kaurav answered May 10, 2021 edited May 10, 2021 by Aashay kaurav Aashay kaurav 292 points comment Share See all 0 reply Please log in or register to add a comment.