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NIELIT 2019 Feb Scientist D - Section D: 11
Lakshman Bhaiya
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Quantitative Aptitude
Apr 3, 2020
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Krithiga2101
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What will be area of the rhombus with equations of sides $ax \pm$ $by \pm c$ = $1$ ?
$\frac{3c^{2}}{ab}$sq. units
$\frac{4c^{2}}{ab}$sq. units
$\frac{2c^{2}}{ab}$sq. units
$\frac{c^{2}}{ab}$sq. units
nielit2019feb-scientistd
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Lakshman Bhaiya
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Option
(
C)
Consider the given equation as $ax\pm by\pm c = 0$ then,
The coordinates of the vertices are (−a/c,0),(a/c,0),(0,b/c),(0,−b/c)
Let d1,d2 be the diagonals of the rhombus.
d1 = 2c/a
d2 = 2c/b
Area = 1/2(d1.d2)
= 2*c^2/ab
Aashay kaurav
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