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(A) $1, -8$

$x^{\frac{2}{3}} + x^{\frac{1}{3}} – 2 = 0\\  \> \\  \text{put }x=1 \\  \implies 1 + 1-2 = 0 \\ \> \\ \text{put } x= -8 \\ \implies (-8)^{\frac{2}{3}} + (-8)^{\frac{1}{3}} – 2 = 4-2 -2 = 0$

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