edited by
564 views
0 votes
0 votes

$21$ mango trees, $42$ apple trees and $56$ orange trees have to be planted in rows such that each row contains the same number of trees of one variety only. Minimum number of rows in which the above trees may be planted is :

  1. $3$
  2. $15$
  3. $17$
  4. $20$
edited by

1 Answer

3 votes
3 votes

HCF of 21, 42 and 56 is 7.

“each row contains the same number of trees”. So Number of trees = 7

And Now each row contains the same number of trees of “one variety only”.

So, 21 mango trees have 3 rows.

42 apple trees have 6 rows

and 56 orange trees have 8 rows.

Total Rows= 3+6+8 = 17

Related questions

0 votes
0 votes
1 answer
1
Lakshman Bhaiya asked Apr 3, 2020
706 views
₹ $49$ were divided among $150$ children. Each girl got $50$ paise and a boy $25$ paise. How many boys were there ?$100$$102$$104$$105$
0 votes
0 votes
1 answer
2
Lakshman Bhaiya asked Apr 3, 2020
722 views
$\left (x^{n}+a^{n} \right)$ is divisible by $(x+a)$ :For all values of $n$Only for even values of $n$Only for odd values of $n$Only for prime values of $n$
0 votes
0 votes
1 answer
3
Lakshman Bhaiya asked Apr 1, 2020
553 views
Find the number of numbers between $300$ to $400$ (both included) that are not divisible by $2,3,4$ and $5$$50$$33$$26$$17$
0 votes
0 votes
1 answer
4
Lakshman Bhaiya asked Apr 1, 2020
1,111 views
By which one of the following should we multiply $152207$ so that the product is $11111111$?$53$$63$$73$$83$
0 votes
0 votes
2 answers
5
Lakshman Bhaiya asked Apr 1, 2020
1,144 views
On dividing $50$ into two parts such that the sum of their reciprocals is $\dfrac{1}{12}$, we get the parts as:$20,30$$24,26$$28,22$$36,14$