clock

Question

A watch which gains $5$ seconds in $3$ minutes was set right at $7$ a.m. In the afternoon of the same day, when the watch indicated quarter past $4$ o'clock, the true time is:

• A. $59 \frac{7}{12}\;\text{min. past 3}$
• B. $4 \;\text{p.m.}$
• C. $58 \frac{7}{11}\;\text{min. past 3}$
• D. $2 \frac{3}{11}\;\text{min. past 4}$

 

A watch which gains 5 seconds in 3 minutes was set right at 7 a.m. In the afternoon of the same day, when the watch indicated quarter past 4 o'clock, the true time is:

A. 59 7 min. past 3 12 B. 4 p.m. C. 58 7 min. past 3 11 D. 2 3 min. past 4 11

Comments

3 min of right clock = (3+112)=3712 min of wrong clock

3/60 hr of right = 37/(12*60) hr of wrong

and wrong clock run 9hr 15 min from 7am to 4:15pm

so (9 + 15/60) = 37/4 hr of wrong = (3/60) * 3 * 60 = 9hr of right clock.

So right clock show 7am + 9hr = 4pm

Answer 1

3 min of right clock = $(3 + \frac{1}{12}) = \frac{37}{12}$ min of wrong clock

3/60 hr of right = 37/(12*60) hr of wrong

and wrong clock run 9hr 15 min from 7am to 4:15pm

so (9 + 15/60) = 37/4 hr of wrong = (3/60) * 3 * 60 = 9hr of right clock.

So right clock show 7am + 9hr = 4pm