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Of the three numbers, the sum of the first two is $45$; the sum of the second and third is $55$ and the sum of the third and thrice the first is $90$. The third number is :

  1. $20$
  2. $25$
  3. $30$
  4. $35$
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$\text{Let the first number is x, the second number is y & the third number is z}$

$\text{According to  the question}$

$x+y=45   ...(1)$

$y+z=55    ...(2)$

$z+3x=90...(3)$

from (1) & (2)

$x-z=-10...(4)$

from (3) & (4):

$x=20$

from equation (1):

$y=25$

from equation (3):

$z=30$

So option $(C)$ is correct.
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