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If $34$ men completed $2/5$th of a work in $8$ days working $9$ hours a day. How many more man should be engaged to finish the rest of the work in $6$ days working $9$ hours a day?

  1. $189$
  2. $198$
  3. $102$
  4. $142$
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$\dfrac{34 \times 8 \times 9}{2/5} = \dfrac{M \times 6 \times 9}{3/5}$

$\implies M = 34 \times 2 = 68.$

Number of men to be added to finish the work $= 68-34 = 34$ men.
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