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The value of $\large\frac{(0.96)^3-(0.1)^3}{(0.96)^2+0.096+(0.1)^2}$ is :

1. $0.86$
2. $0.95$
3. $0.97$
4. $1.06$

These type of questions are based on direct formulae of a^3 -b^3 and/or a^2 – b^2 etc.

Here, $a^{3}-b^{3} =(a-b)(a ^{2}+ b ^{2} +ab)$

So Simply, from question, a= 0.96 and b=0.10

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