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The sum of the squares of the fifth and the eleventh term of an AP is $3$ and the product of the second and fourteenth term is equal to $x$. Find the product of the first and fifteenth term of an AP.

1. $\dfrac{(58x-39)}{45} \\$
2. $\dfrac{(98x-39)}{72} \\$
3. $\dfrac{(116x-39)}{90} \\$
4. $\dfrac{(98x-39)}{90}$

1
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