198 views

If $(-4,0),(1,-1)$ are two vertices of a triangle whose area is $4$ Sq units then its third vertex lies on:

1. $y=x$
2. $5x+y+12=0$
3. $x+5y-4=0$
4. $x-5y+4=0$

by
168 points

1 vote
1
298 views