$\frac{a_1}{a_2}=\frac{3}{1}$

Does the above equation mean side length of square 1 is 3 and side length of square 2 is 1?

Does the above equation mean side length of square 1 is 3 and side length of square 2 is 1?

592 views

1 vote

According to the question:

$\frac{\text{area of 1st square}}{\text{area of 2nd square}}=\frac{9}{1}$

$\because$ Area of square is $a^2$,where $a$ is side of square.

Assume that side of square1 is $a_1$ & side of square 2 is $a_2$.

$\implies$ $\frac{(a_1)^2}{(a_2)^2}=\frac{9}{1}$

$\implies$ $\frac{a_1}{a_2}=\frac{3}{1}$

$\therefore$ Side of square1 is $3$ and side of square2 is $1$

$\because$ perimeter of square is $4*a$,so there ratio is;

$\implies$ $\frac{4*a_1}{4*a_2}$

$\implies$ $\frac{4*3}{4*1}$

$\implies$ $3:1$

Option (b) is correct.

$\frac{\text{area of 1st square}}{\text{area of 2nd square}}=\frac{9}{1}$

$\because$ Area of square is $a^2$,where $a$ is side of square.

Assume that side of square1 is $a_1$ & side of square 2 is $a_2$.

$\implies$ $\frac{(a_1)^2}{(a_2)^2}=\frac{9}{1}$

$\implies$ $\frac{a_1}{a_2}=\frac{3}{1}$

$\therefore$ Side of square1 is $3$ and side of square2 is $1$

$\because$ perimeter of square is $4*a$,so there ratio is;

$\implies$ $\frac{4*a_1}{4*a_2}$

$\implies$ $\frac{4*3}{4*1}$

$\implies$ $3:1$

Option (b) is correct.