For first digit there is only 1 choice i.e. 7.
For second digit number of choices= 5 (0,2,4,6,8)
For 3rd and 4th digit
S.N. |
Second Last Digit |
Range of Last digit |
Number of choices |
1 |
0 |
1-9 |
9 |
2 |
1 |
2-9 |
8 |
3 |
2 |
3-9 |
7 |
4 |
3 |
4-9 |
6 |
5 |
4 |
5-9 |
5 |
6 |
5 |
6-9 |
4 |
7 |
6 |
7-9 |
3 |
8 |
7 |
8-9 |
2 |
9 |
8 |
9 |
1 |
|
|
|
Total choices=45 |
Total no of different number plate possible=1*5*45=225
Hence Option (1)225 is the Answer.