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NIELIT 2019 Feb Scientist C - Section C: 19
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If $a^{x}=b, b^{y}=c$ and $c^{z}=a$, then $xyz$ equals:
$abc$
$\dfrac{1}{abc}$
$1$
None
nielit2019feb-scientistc
algebra
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Apr 1, 2020
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Quantitative Aptitude
Lakshman Patel RJIT
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ANSWER: C
Take log of both side and solve.
answered
Nov 19, 2020
Devwritt
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$\textrm{Given that: }$
$a^x=b ….(1)$
$b^y=c ….(2)$
$c^z=a….(3)$
$\textrm{taking log in above equations we get:}$
$\implies$ $xlog_2a=log_2b$
$\implies$ $x=\frac{log_2b}{log_2a}….(4)$
$\textrm{in the same way}$
$y=\frac{log_2c}{log_2b}….(5)$
$z=\frac{log_2a}{log_2c}…..(6)$
$\textrm{multiply equations (4),(5),(6).}$
$\implies$ $x*y*z=\frac{log_2b}{log_2a}*\frac{log_2c}{log_2b}*\frac{log_2a}{log_2c}$
$\implies$ $x*y*z=1$
$\textrm{Option C is correct.}$
answered
Nov 24, 2020
Hira Thakur
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NIELIT 2019 Feb Scientist C - Section D: 15
The simplified form of $\left[ \left ( \left( \dfrac{a+1}{a-1}\right)^2+3 \right)\div \left( \left( \dfrac{a+1}{a-1}\right)^2+3\right) \right] \div \left [\left( \dfrac{a^{3}+1}{a^{3}-1}\right)-\dfrac{2a}{a-1} \right]$ is: $a-1$ $1-a$ $-1$ $1$
The simplified form of $\left[ \left ( \left( \dfrac{a+1}{a-1}\right)^2+3 \right)\div \left( \left( \dfrac{a+1}{a-1}\right)^2+3\right) \right] \div \left [\left( \dfrac{a^{3}+1}{a^{3}-1}\right)-\dfrac{2a}{a-1} \right]$ is: $a-1$ $1-a$ $-1$ $1$
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Lakshman Patel RJIT
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nielit2019feb-scientistc
algebra
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NIELIT 2019 Feb Scientist C - Section D: 23
$₹6500/-$ were divided among a certain number of persons. If there had been $15$ more persons, each would have got $₹30/-$ less. Find the original number of persons. $50$ $60$ $45$ $55$
$₹6500/-$ were divided among a certain number of persons. If there had been $15$ more persons, each would have got $₹30/-$ less. Find the original number of persons. $50$ $60$ $45$ $55$
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Apr 1, 2020
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nielit2019feb-scientistc
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NIELIT 2019 Feb Scientist C - Section D: 30
A charitable trust donates $28$ different books of Maths, $16$ different books of science and $12$ different books of social science to poor students. Each student is given maximum number of books of only one subject of their interest and each student got equal number of books. Find the total number of students who got books. $14$ $10$ $12$ $15$
A charitable trust donates $28$ different books of Maths, $16$ different books of science and $12$ different books of social science to poor students. Each student is given maximum number of books of only one subject of their interest and each student got equal number of books. Find the total number of students who got books. $14$ $10$ $12$ $15$
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Apr 1, 2020
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Lakshman Patel RJIT
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778
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nielit2019feb-scientistc
quantitative-aptitude
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NIELIT 2019 Feb Scientist C - Section C: 3
The factors of $(x^{2}+4y^{2}+4y-4xy-2x-8)$ are: $(x-2y-4)(x-2y+2)$ $(x-y+2)(x-4y-4)$ $(x+2y-4)(x+2y+2)$ None of these
The factors of $(x^{2}+4y^{2}+4y-4xy-2x-8)$ are: $(x-2y-4)(x-2y+2)$ $(x-y+2)(x-4y-4)$ $(x+2y-4)(x+2y+2)$ None of these
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Apr 1, 2020
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Quantitative Aptitude
Lakshman Patel RJIT
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371
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778
78
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nielit2019feb-scientistc
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1
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NIELIT 2019 Feb Scientist C - Section D: 19
If $x=\dfrac{\sqrt{10}+\sqrt{2}}{2}, \: \: y=\dfrac{\sqrt{10}-\sqrt{2}}{2}$ then the value of $\log _{2}(x^{2}+xy+y^{2})$ is: $0$ $1$ $2$ $3$
If $x=\dfrac{\sqrt{10}+\sqrt{2}}{2}, \: \: y=\dfrac{\sqrt{10}-\sqrt{2}}{2}$ then the value of $\log _{2}(x^{2}+xy+y^{2})$ is: $0$ $1$ $2$ $3$
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Apr 1, 2020
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Lakshman Patel RJIT
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778
72
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nielit2019feb-scientistc
quantitative-aptitude
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