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2 Answers

1 votes
1 votes
Given that:

$a^x=b ….(1)$

$b^y=c ….(2)$

$c^z=a….(3)$

taking log in above equations we get:

$\implies xlog_2 a=log_2b$

$\implies$ $x=\frac{log_2 b}{log_2 a}….(4)$

in the same way

 $y=\frac{log_2 c}{log_2 b}….(5)$

$z=\frac{log_2 a}{log_2 c}…..(6)$

multiply equations (4),(5),(6).

$\implies x*y*z=\frac{log_2b}{log_2a}*\frac{log_2c}{log_2b}*\frac{log_2a}{log_2c}$

$\implies x*y*z=1$
Option (C) is correct.
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