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An hour after Aishwarya started from her college towards Ananya’s home, a distance of $53$ km, Ananya started from her home on the same road towards Aishwarya’s college. If Aishwarya’s speed was $4$ km per hour and Ananya’s was $3$ km per hour, how many km from Ananya’s home did the two meet?

  1. $24$
  2. $22$
  3. $21$
  4. $19.5$
in Quantitative Aptitude recategorized by
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Aishwarya $\Longrightarrow \underbrace{\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;}_{53\;\text{km}} \Longleftarrow $ Ananya

In $1$ hour Aishwarya distance $D_{1} = 4\;\text{km/hour} \times 1\;\text{hour} = 4\;\text{km}$

Remaining distance $D = 53\;\text{km}-D_{1}\;\text{km} = 53\;\text{km}-4\;\text{km}  = 49\;\text{km}$

Relative speed $S_{r} = 4\;\text{km/hour} + 3\;\text{km/hour} = 7\;\text{km/hour}$

Time when they meet $T = \dfrac{49\;\text{km}}{7\;\text{km/hour}} = 7\;\text{hours}$

Ananya distance in $7\;\text{hours} = 7\;\text{hour} \times 3\;\text{km/hour} = 21\;\text{km}.$


Aishwarya distance in $7\;\text{hours} = 7\;\text{hour} \times 4\;\text{km/hour} = 28\;\text{km},$ and distance traveled by Ananya $= 49 - 28 = 21\;\text{km}.$

Thus they meet $21\;\text{km}$ from the Ananya home.

So, the correct answer is $(C).$
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