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If $\div$ means $+$, $–$ means $\div$ , $\times$ means $–$ and $+$ means $\times$, then

$\dfrac{\left ( 3\times 4 \right )-8\times 4}{4+8\times 2 +16 \div 1}=?$

1. $1$
2. $-1$
3. $2$
4. $0$

If $\div$ means $+$, $–$ means $\div$ , $\times$ means $–$ and $+$ means $\times$, then

$\dfrac{\left ( 3\times 4 \right )-8\times 4}{4+8\times 2 +16 \div 1} = \dfrac{\left ( 3- 4 \right )\div8- 4}{4\times 8- 2 \times 16 +1} = \dfrac{-33}{8}$
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