Lakshman Patel RJIT
asked
in Quantitative Aptitude
Mar 31, 2020
recategorized
Aug 15, 2020
by Lakshman Patel RJIT

469 views
0 votes

$A$ can run $200\;m$ in $35\; sec,$ so in $1\;sec\; A$ can run $\dfrac{200}{35}\;m = \dfrac{40}{7}\;m = 5.71\;m$

And, $B$ can run $200\;m$ in $38\;sec,$ so in $1\;sec\; B$ can run $\dfrac{200}{38}\;m = \dfrac{100}{19}\;m = 5.26\;m$

Now, $B$ run $35\;sec$ then distance cover by $B = 5.26\;m \times 35 = 184.1\:m$

$\therefore\;A$ can beat $B$ by $200 – 184.1 = 15.9\:m \approx 15\dfrac{15}{19}\;m.$

So, the correct answer is $(C).$

And, $B$ can run $200\;m$ in $38\;sec,$ so in $1\;sec\; B$ can run $\dfrac{200}{38}\;m = \dfrac{100}{19}\;m = 5.26\;m$

Now, $B$ run $35\;sec$ then distance cover by $B = 5.26\;m \times 35 = 184.1\:m$

$\therefore\;A$ can beat $B$ by $200 – 184.1 = 15.9\:m \approx 15\dfrac{15}{19}\;m.$

So, the correct answer is $(C).$