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Two students appeared at an examination. One of them secured $9$ marks more than the other and his marks were $56\%$ of the sum of their marks. The marks obtained by them are

1. $39, 30$
2. $41, 32$
3. $42, 33$
4. $43, 34$

$\textrm{Let assume that A & B are two students.}$

$\textrm{Now assume B’s marks are x & A’s marks are x+9}$

$\Rightarrow$ $A=(x+9)$

$\Rightarrow$ $B=x$

$\Rightarrow$ $\textrm{(x+9)=x+x+9(56%)}$

$\Rightarrow$ $25x+225=28x+126$

$\Rightarrow$ $3x=99$

$\Rightarrow$ $x=33$

$\textrm{So B=33,A=42}$

$\textrm{Option C}$
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