The length of a rope, to which a cow is tied, is increased from $19$ m to $30$ m. How much additional ground will it be able to graze ? Assume that the cow is able to move on all sides with equal ease. Use $\pi = \frac{22}{7}$ in your calculations.

Option B. 1694 sq m

Area of circle = π$r^{2}$

Additional ground will cow be able to graze = Outer circle – Inner circle

= π$30^{2}$ – π$19^{2}$

=$\frac{22}{7}$[900 – 361]

= $\frac{22}{7}$ * 539

= 1694