NIELIT 2017 DEC Scientist B - Section A: 59

Question

What is the measure of the radius of the circle that circumscribes a triangle whose sides measure $9, 40$ and $41$?

• A. $6$
• B. $4$
• C. $24.5$
• D. $20.5$

Answer 1

Option D. 20.5

Triangle with sides 9, 40 and 41 is a right triangle.
$9^{2}$+$40^{2}$=$41^{2}$
In a right angled triangle, the radius of the circle that circumscribes the triangle is half the hypotenuse.
Therefore, the radius of the circle that circumscribes the triangle = $\frac{41}{2}$ = 20.5