Given that, Anil alone can do a job in $20$ days, and Sunil alone can do a job in $40$ days.
- Anil $\rightarrow 20$ days
- Sunil $\rightarrow 40$ days
LCM of $20$ and $40 \Rightarrow 40\;\text{units}$ (Total work)
- Anil efficiency $=\frac{40}{20} \Rightarrow 2$
- Sunil efficiency $= \frac{40}{40}\Rightarrow 1$
Work done by Anil in $3$ days $ = 2 \times 3 = 6\;\text{units}$
Now, remaining work $ = 40 – 6 = 34\;\text{unit}$
Let the number of days Anil and Sunil done the work together be $x$ days.
Bimal has done $10\%$ of the work $ = 40 \times \frac{10}{100} = 4\;\text{units}$
Remaining work done by Anil and Sunil $ = 34-4=30\;\text{units}$
The number of days Anil and Sunil did the work together $ x = \frac{30}{(2+1)} = \frac{30}{3} = 10$ days.
$\therefore$ The total time to complete the work $ = x + 3 = 10 + 3 = 13$ days.
Correct Answer : B