# CAT2007-42

754 views

Answer the following question based on the information given below:

A low-cost airline company connects ten Indian cities, A to J. The table below gives the distance between a pair of airports and the corresponding price charged by the company. Travel is permitted only from a departure to an arrival airport. The customers do not travel by a route where they have to stop at more than two intermediate airports.

 Sector No. Airport of Departure Airport of Arrival Distance between the airports (km.) Price (Rs.) 1 A B 560 670 2 A C 790 1350 3 A D 850 1250 4 A E 1245 1600 5 A F 1345 1700 6 A G 1350 2450 7 A H 1950 1850 8 B C 1650 2000 9 B H 1750 1900 10 B I 2100 2450 11 B J 2300 2275 12 C D 460 450 13 C F 410 430 14 C G 910 1100 15 D E 540 590 16 D F 625 700 17 D G 640 750 18 D H 950 1250 19 D J 1650 2450 20 E F 1250 1700 21 E G 970 1150 22 E H 850 875 23 F G 900 1050 24 F I 875 950 25 F J 970 1150 26 G I 510 550 27 G J 830 890 28 H I 790 970 29 H J 400 425 30 I J 460 540

What is the lowest price, in rupees, a passenger has to pay for travelling by the shortest route from A to J?

1. 2275
2. 2850
3. 2890
4. 2930
5. 3340

1 vote
Option (A)

A to H to J = 1850 + 425 = 2275
42 points 1 2

Ans (E).

Since it asking a passenger has to pay for traveling by the shortest route from A to J.

There are multiples routes from A to J and shorted is A-G-J. And the price is 2450 + 890 = 3340.

32 points 1 2

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