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Each of $74$ students in a class studies at least one of the three subjects $\text{H, E}$ and $\text{P}$. Ten students study all three subjects, while twenty study $\text{H}$ and $\text{E}$, but not $\text{P}$. Every student who studies $\text{P}$ also studies $\text{H}$ or $\text{E}$ or both. If the number of students studying $\text{H}$ equals that studying $\text{E}$, then the number of students studying $\text{H}$ is _________

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Given that,

- $ n(H \cup E \cup P) = 74 $
- $ n( H \cap E \cap P) = 10 $
- $ n(H \cap E) = 20 $
- Only $ P = 0 $

We can draw the Venn diagram,

Here, given that $ : b=20, g=10, d=0 $

The number of students studying $ H = $ The number of students studying $E$

$ a + b + e + g = b + c + g + f $

$ \Rightarrow a + 20 + e + 10 = 20 + c + 10 + f $

$ \Rightarrow \boxed{a + e = c + f} \quad \longrightarrow (1) $

We have, $ a + b + c + d + e + f + g = 74 $

$ \Rightarrow a + 20 + c + 0 + e + f + 10 = 74 $

$ \Rightarrow a + e + c + f = 44 $

$ \Rightarrow 2(a+e) = 44 \quad [ \because \text{From equation (1)}]$

$ \Rightarrow \boxed{a + e = 22} $

$\therefore$ The number of students who studies $ H = a + b + e + g = 22 + 20 + 10 = 52.$

Correct Answer $: 52$