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From a triangle $\text{ABC}$ with sides of lengths $40$ ft, $25$ ft and $35$ ft, a triangular portion $\text{GBC}$ is cut off where $\text{G}$ is the centroid of $\text{ABC}$. The area, in sq ft, of the remaining portion of triangle $\text{ABC}$ is

- $225 \sqrt{3} \\$
- $\dfrac{500}{ \sqrt{3}} \\$
- $\dfrac{275 }{\sqrt{3}} \\$
- $\dfrac{250 }{\sqrt{3}} $