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A person who has a certain amount with him goes to market. He can buy $50$ oranges or $40$ mangoes. He retains $10\%$ of the amount for taxi fares and buys $20$ mangoes and of the balance he purchases oranges. Number of oranges he can purchase is

1. $36$
2. $40$
3. $15$
4. $20$

Let a person have $₹ \; 100.$

He can buy $50$ oranges or $40$ mangoes.

• Price of each orange $= \frac{100}{50} = 2$
• Price of each mango $= \frac{100}{40} = \frac{5}{2}$

He retains $10\%$ of the amount for the amount for taxi fares, then remaining amount $= 100 – 10 = ₹ \; 90$

He buys $20$ mangoes. The price of $20$ mangoes $= 20 \times \frac{5}{2} = ₹ \; 50$

Remaining amount $= 90 – 50 = ₹ \; 40$

He purchases oranges from the remaining amount.

$\therefore$ The number of oranges he can purchase $= \frac{40}{2} = 20$ oranges.

Correct Answer $: \text{D}$

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