in Quantitative Aptitude edited by
281 views
0 votes
0 votes

A young girl counted in the following way on the fingers of her left hand. She started calling the thumb $1$, the index finger $2$, middle finger $3$, ring finger $4$, little finger $5$, then reversed direction, calling the ring finger $6$, middle finger $7$, index finger $8$, thumb $9$, then back to the index finger $10$, middle finger for $11$, and so on. She counted up to $1994$. She ended on her.

  1. thumb
  2. index finger
  3. middle finger
  4. ring finger
in Quantitative Aptitude edited by
13.4k points
281 views

1 Answer

0 votes
0 votes

Given that, a young girl started calling:

  • Thumb – $1,9$
  • Index Finger – $2,10$
  • Middle Finger – $3,11$
  • Ring Finger – $4,12$
  • Little Finger – $5,13$
  • Ring Finger – $6,14$
  • Middle Finger – $7,15$
  • Index Finger – $8,16$

From the above information, we can get the pattern: $1,9,17,25, \dots$

We can write, $8n+1, n=0,1,2, \dots$

She counted upto $1994$

That means, $1994 \% 8 = 2$

$\therefore$ If she counted upto $1994,$ she ended on her index finger.

Correct Answer $: \text{B}$

10.3k points

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true