We have $x^2 – x – 6 = x+2 \qquad \to (1)$
and $-(x^2-x-6) = x+2 \qquad \to (2)$
From $(1),$ we get $x^2-2x -8 = 0 \implies (x-4)(x+2) = 0 \implies x = 4, -2$
From $(2),$ we get $x^2-4 = 0 \implies x^2 = 4 \implies x = \pm 2$
So, the roots of the equation are $4,-2,2$
Product of the roots $ = -16$
Correct Option: D