in Quantitative Aptitude retagged by
259 views
1 vote
1 vote

A chemist mixes two liquids $1$ and $2$. One litre of liquid $1$ weighs $1$ kg and one litre of liquid $2$ weighs $800$ gm. If half litre of the mixture weighs $480$ gm, then the percentage of liquid $1$ in the mixture, in terms of volume, is

  1. $85$
  2. $70$
  3. $75$
  4. $80$

 

in Quantitative Aptitude retagged by
13.4k points
259 views

1 Answer

1 vote
1 vote

$\textbf{First Method:}$

Given that,

  • One litre of liquid $1$ weighs $ = 1 \; \text{kg} = 1000 \; \text {gm}.$
  • One litre of liquid $2$ weighs $ = 800 \; \text{gm}.$
  • And half litre of mixture weighs $ = 480 \; \text{gm}.$

When both liquids given and mixture also given, we can use the alligation method.

 Half litre of mixture weighs is $ 480 \; \text{gm}.$

Therefore, the weighs of liquid $1$ and liquid $2$ also become half.

Now, we can apply the alligation method.

$\therefore$ Percentage of liquid $1$ in the mixture $ = \frac{4}{5} \times 100 = 80\%.$

$ \textbf{Second Method}:$

$1$ litre mixture weigh is $480 \times 2 = 960 \text{gm}.$

$\therefore$ Percentage of liquid $1$ in the mixture $ = \frac{4}{5} \times 100 = 80\%.$

Correct Answer $: \text{D}$

edited by
10.3k points
Answer:

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true