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In the figure below, $\angle \text{MON} = \angle \text{MPO} = \angle \text{NQO} = 90^{\circ}$ and $\text{OQ}$ is the bisector of  $\angle \text{MON}$ and $\text{QN} = 10, \text{OR} = 40/7$. Find $\text{OP}$.

  1. $4.8$
  2. $4.5$
  3. $4$
  4. $5$
in Quantitative Aptitude edited by
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