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$\text{P, Q and R}$ are three consecutive odd numbers in ascending order. If the value of three times $\text{P}$ is three less than two times $\text{R}$, find the value of $\text{R}$.

1. $5$
2. $7$
3. $9$
4. $11$

Given that $P, Q$ and $R$ are consecutive odd numbers in ascending orders.

We can take $P = x,Q = x+2$ and $R = x+4$

According to the question$:3P = 2R – 3$

$\implies 3x = 2(x+4) – 3$

$\implies 3x = 2x + 8 – 3$

$\implies x= 5$

$\therefore R = x+4 = 5 + 4 = 9.$

So, the correct answer is $(C).$
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