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Can someone explain answer for this question(26)?

+1
all options are wrong answer is $\frac{1}{3}$

Total number of balls = 8 + 7 + 6 = 21

Let E be the event of selecting neither red nor green ball

Then n(E) = 7

Required probability = 7/21 = 1/3
answered by (298 points) 1 1 5