$A$ does $\dfrac{1}{2}^{th}$ work in $7$ days
So, in $\dfrac{7}{\dfrac{1}{2}} = 7 \times 2 = 14 $ days $A$ can complete the whole work
$B$ does $\dfrac{1}{3}^{th}$ work in $14$ days
So, in $\dfrac{14}{\dfrac{1}{3}} = 14 \times 3 = 42 $ days $B$ can complete the whole work
Now, remaining work = $\left ( 1 - \dfrac{1}{2} + \dfrac{1}{3} \right ) = \left ( 1 - \dfrac{5}{6} \right ) = \dfrac{6 - 5}{6} = \dfrac{1}{6}$
& $20\%$ of the remaining work = $\dfrac{1}{6} \times 20\% =\dfrac{1}{6} \times \dfrac{1}{5} =\dfrac{1}{30}$
∴ $C$ does $\dfrac{1}{30}^{th}$ work in $\dfrac{28}{5}$ days
So, in $\dfrac{\dfrac{28}{5}}{\dfrac{1}{30}} = \dfrac{28}{5} \times 30 = 28 \times 6 = 168$ days $C$ can complete the whole work
Now, LCM of $(14, 42, 168) = 168$
∴ Total units of work = $168 $ units
∴ $A$ can complete $\dfrac{168}{14} = 12$ units of work in $1$ day
$B$ can complete $\dfrac{168}{42} = 4$ units of work in $1$ day
$C$ can complete $\dfrac{168}{168} = 1$ units of work in $1$ day
When $A, B, C$ works together in $1$ day total work done = $12+4+1 = 17$ units
∴ To complete $168$ units $A, B, C $ have to work for $\dfrac{168}{17} = 9.88$ days
∴ To complete the whole work $A, B, C$ have to work together for $9.88$ days.