for (x-a)(x-b)<0

x lies between a and b exclusive.

a<x<b

for (p-0)(p-1)<0

p lies between 0 and 1

x lies between a and b exclusive.

a<x<b

for (p-0)(p-1)<0

p lies between 0 and 1

Aptitude Overflow

+3 votes

p(p−1)<0 what is value of p please solve step by step

options are

(A) (–∞, 0)

(B) (0, 1)

(C) (1, ∞)

(D) (0, ∞)

options are

(A) (–∞, 0)

(B) (0, 1)

(C) (1, ∞)

(D) (0, ∞)

+3 votes

Best answer

This can be understood by drawing on a graph. However it can also be done by hit-and-trial/option elimination :

a)If p lies between infinity and 0, suppose p is -10, then p-1=-11. Product is greater than 0

b)p lies between 0 and 1 , suppose p is 0.9 and p-1= -(.1) **Less than 0**

c) Let p=10 then p-1=9 product is greater than 0

d) Let p=8, p-1=7 Product is greater than 0

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