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Car  A left from X for Y at 9:00 a.m.Car B left from Y to X at 10:00 a.m.XY=180 km.

Speed of A and B are 30 and 20 kmph respectively.Find their meeting time
in Quantitative Aptitude
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Best answer

We know that,

If two objects are moving at speeds S1 and S2, their relative speed is
S1 + S2, if they are moving in opposite direction and
S1 – S2, if they are moving in the same direction.
And,

Time is taken to meet/catch =Initial distance separating them/ (Relative Speed i.e. S1 ∓ S2)

Car A starts at 9:00 am & Car B starts at 10:00 am

By 10:00 am car A already travels (30 x 1)= 30 km.

So, by 10:00 am The distance between car A and car B is (180 - 30) = 150 km.

∴ Time taken to meet = 150 / (30 + 20)

                                   = 150/50

                                   = 3 hrs.

Car A and Car B will meet at (10 + 3)= 13 i.e at 1:00 pm.

 

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