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A coin is tossed 10 times Find the probablity of obtaining head at least once

Probability of obtaining head at least once    =  1 - ( Probability of obtaining tail all 10 times)

= 1 - (1/2)^10

= 1023/1024

Therefore , probability is 1023/1024
selected
Sample space size $= 1024$
No. of favourable cases $= 1024-1=1023$
Probability $= \frac{1023}{1024} =99.90 \%$
answered by (890 points) 1 2 19
1023/1024

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