1,119 views

3 Answers

Best answer
2 votes
2 votes
Probability of obtaining head at least once    =  1 - ( Probability of obtaining tail all 10 times)

                                                                       = 1 - (1/2)^10

                                                                       = 1023/1024 

Therefore , probability is 1023/1024
selected by
2 votes
2 votes
Sample space size $= 1024$
No. of favourable cases $= 1024-1=1023$
Probability $=  \frac{1023}{1024}  =99.90 \%$

Related questions

0 votes
0 votes
1 answer
3
Lakshman Bhaiya asked Mar 31, 2020
1,397 views
If a fair coin is tossed $5$ times and comes up heads four times out of five. Then if the coin is tossed a sixth time under the same conditions, the probability of it tur...
2 votes
2 votes
1 answer
4
Lakshman Bhaiya asked Mar 31, 2020
690 views
Two dice are thrown simultaneously. The probability of obtaining a total score of $5$ is$1/18$$1/12$$1/9$None of these
2 votes
2 votes
2 answers
5
Rishav Kumar Singh asked Aug 1, 2018
1,482 views
You have to play three games with opponents A and B in a specified sequence. You win the series if you win two consecutive games. A is a stronger player than B. Which seq...