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According to the question , B's speed is more than A so it will take less time to cover the distance between X and Y. 

Let distance between  X and Z  =  x

 So distance between Y and Z   =  27 - x [ As B returns towards X and meet A at Z in that process ]

 For meeting , time taken throughout must be same . Thus we have :

            x / 5    =   (27 + 27 - x) / 7

 ==>     x / 5    =   (54 - x) / 7

 ==>     7x       =   270 - 5x

 ==>    12x      =   270

 ==>     x        =   22.5

 Hence B) should be the correct option.    

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