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A and B walk from X to Y, a distance of 27 km at 5 kmph and 7 kmph respectively. B reaches Y and immediately turns back meeting A at Z. What is the distance from X to Z?

1. 25 km
2. 22.5 km
3. 24 km
4. 20 km

According to the question , B's speed is more than A so it will take less time to cover the distance between X and Y.

Let distance between  X and Z  =  x

So distance between Y and Z   =  27 - x [ As B returns towards X and meet A at Z in that process ]

For meeting , time taken throughout must be same . Thus we have :

x / 5    =   (27 + 27 - x) / 7

==>     x / 5    =   (54 - x) / 7

==>     7x       =   270 - 5x

==>    12x      =   270

==>     x        =   22.5

Hence B) should be the correct option.

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