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0 votes

The fourth term of an arithmetic progression is 8. What is the sum of the first 7 terms of the arithmetic progression?

- 7
- 64
- 56
- cannot be determined

+2 votes

As here we have 7 terms so we can assume the terms of the A.P. as : a - 3d , a - 2d , a - d , a , a + d , a + 2d and a + 3d

Thus sum of 7 terms of the A.P, = (a - 3d) + (a - 2d) + (a - d) + (a) + (a + d) + (a + 2d) + (a - 3d)

= 7a

= 7(8) = 56 [ As fourth term of A.P. = a = 8 is given in the question ]

**Hence C) should be the correct answer.**

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