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If $\log_{7} \log_{5} (x+5x+x)=0$; find the value of $x$.

  1. 1
  2. 0
  3. 2
  4. None of these
asked in Quantitative Aptitude by (4.8k points) 38 105 176 | 71 views
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Question should have been : If log7log5(x+5x+x)=0 , then find x .

Solving accordingly, log7(7x)=50

=> log7(7x)=1 

=> 7x=7 Hence x=1 

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