b right?

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**Answer: B**

$\#$ways to select $6$ tickets when the highest number is between $1$ to $7$ with replacement = $7^6$

$\#$ways to select $6$ tickets when the highest number is between $1$ to $6$ with replacement = $6^6$

Now $7^6 – 6^6$ will give all the possibilities when highest number is $7$

$\#$ways to select $6$ tickets out of $10$ with replacement = $10^6$

$\therefore \text{Required probability} = \large\frac{7^6 – 6^6}{10^6}$