in Quantitative Aptitude edited by
3,206 views
4 votes
4 votes

Ten tickets numbered $1, 2, 3, \ldots 10.$ Six tickets are selected at random one at a time with replacement.  The probability of the largest number appearing on the selected ticket being $7$ is ________

  1. $(7^6 +1)/10^6$
  2. $(7^6 - 6^6)/10^6$
  3. $(7^6+6^6)/10^6$
  4. $6^6/10^6$
in Quantitative Aptitude edited by
by
34 points
3.2k views

2 Comments

b right?
2
2
B i guest
0
0

1 Answer

1 vote
1 vote

Answer: B

$\#$ways to select $6$ tickets when the highest number is between $1$ to $7$ with replacement = $7^6$

$\#$ways to select $6$ tickets when the highest number is between $1$ to $6$ with replacement = $6^6$

Now $7^6 – 6^6$ will give all the possibilities when highest number is $7$

$\#$ways to select $6$ tickets out of $10$ with replacement = $10^6$

$\therefore \text{Required probability} = \large\frac{7^6 – 6^6}{10^6}$

by
138 points
Answer:

Related questions

5 votes
5 votes
1 answer
1
Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true