in Quantitative Aptitude
1,182 views
3 votes
3 votes

The largest value of $\min (2 + x^{2} , 6 - 3x)$ when $x > 0$ is

  1. $1$ 
  2. $2$ 
  3. $3$ 
  4. $4$
in Quantitative Aptitude
8.1k points
1.2k views

2 Comments

what is mm here? is it minimum ?
0
0
it is min. Corrected now
1
1

2 Answers

3 votes
3 votes
Best answer

For minimum, 

equating

$2 + x2 = 6 - 3x$

$x2 + 3x - 4 = 0$

$x = 1, -4$

Since $x > 0,$ so value occurs at $x = 1.$

At $x = 1$

$2+x^{2}=3$

$6 - 3x = 3.$

it means the largest value of the function  $min( 2 + x^2 , 6 − 3x)$

                                                                           $min( 3, 3)$ is $3$

The correct option is C.

selected by
3.0k points
2 votes
2 votes

PUT THE DIFFERENT VALUE OF X

​​​​​​​

edited by
13.7k points

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true