(12) and (45) both can be with blue balls at same time , where is that case?

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2 votes

Choose the correct option:

Boxes numbered $1, 2, 3, 4$ and $5$ are kept in a row, and they are to be filled with either a red or a blue ball, such that no two adjacent boxes can be filled with blue balls. How many different arrangements are possible, given that all balls of a given colour are exactly identical in all respects?

- $8$
- $10$
- $15$
- $22$

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Total number of ways of filling the 5 boxes numbered as (1, 2, 3, 4 and 5) with either blue or red balls = 2^{5} = 32.

Now, we determine the number of ways of filling the boxes such that the adjacent boxes are filled with blue.

Two adjacent boxes with blue can be obtained in 4 ways, i.e., (12), (23), (34) and (45).

Three adjacent boxes with blue can be obtained in 3 ways, i.e., (123), (234) and (345).

Four adjacent boxes with blue can be obtained in 2 ways, i.e., (1234) and (2345).

And all 5 boxes can have blue in only 1 way.

Hence, the total number of ways of filling the boxes such that adjacent boxes have blue = (4 + 3 + 2 +1) = 10.

Hence, the number of ways of filling up the boxes such that no two adjacent boxes have blue = 32 - 10 = 22

**The correct option is D.**