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The sides of a triangle are $5, 12$ and $13$ units respectively. A rectangle is constructed which is equal in area to the triangle and has a width of 10 units. Then the perimeter of the rectangle is

1. $30$
2. $26$
3. $13$
4. None of these

ABC forms a right angled triangle since ($12^{2} + 5^{2} = 13^{2}$)

Area of triangle ABC = 0.5 * 12 * 5 = 30

As given in Question  (A rectangle is constructed which is equal in area to the triangle)

Let L be the length of the rectangle and width of 10 units.

Then , area of rectangle = 30 = 3 * 10 = L * 10

So L = 3 units

Perimeter of rectangle = 2(10 + 3) = 26.

Hence B is the Correct option.

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