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$\frac{55^{3}+45^{3}}{55^{2}- 55 \times 45 + 45^{2}}$

We know that

$\therefore (a^{3}+b^{3}=(a+b)(a^{2}-ab+b^{2}))$

$ (a^{3}+b^{3}=(a+b)(a^{2}-ab+b^{2})$

So,

$=\frac{(55+45)(55^{2}-55 \times 45+45^{2})}{(55^{2}-55 \times 45+45^{2})}$

$=(55+45)$$=100$

 

Hence,Option(A)100.
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