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The amount of money invested (in rupees crore) in the core infrastructure areas of two districts, Chittoor and Khammam, Andhra Pradesh as follows:

By what percent was the total investment in the two districts more in 1996 as compared to that in 1995?

1. $14$%
2. $21$%
3. $24$%
4. $18$%
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total investment in 1995 = 10004.7

total investment in 1996 = 11841.5

% increase =  (11841.5 - 10004.7 / 10004.7) * 100 =18.36%

hence option d
answered by (1.4k points) 2 5 9

Total investment in $1995 = \left (2981.1 + 7081.6 \right) = 10062.7 \hspace{0.1cm}Rs.$

Whereas, Total investment in $1996 = \left (3489.5 + 8352.0 \right) = 11841.5 \hspace{0.1cm}Rs.$

∴ Total investment of $1996$ is $\left [\dfrac{(11841.5-10062.7)}{10062.7} = 0.1767 \hspace{0.1cm} \right ] i.e. \hspace{0.1cm} 17.67\%$ greater than the total investment of $1995$.

The answer will be Option D )

answered by (2.3k points) 5 8 14