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The points of intersection of three lines, $2X + 3Y - 5 = 0, 5X - 7Y + 2 = 0$, and $9X-5Y-4 =0$:

  1. form a triangle.
  2. are on lines perpendicular to each other.
  3. are on lines parallel to each other.
  4. are coincident.
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IF THREE LINES ARE  COINCIDENT THEN AREA OF TRIANGLE   MUST BE  ZERO$(0)$

                                                               $(OR)$

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SOLVE  OF THE THESE THREE LINES AND GET THE INTERSECTION POINT.
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Good explanation sir

thank you
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